# Neco Gce Physics Obj & Essay Answer Now Available

PHYSIC OBJ
01-10: EDCCACDCAC
11-20: BBBDAEBCCD
21-30: BDAEADABCA
31-40: CDACCBCEEA
41-50: CCADEBCADA
51-60: CECADADDCE

COMPLETED.

Theory part I. Answer six (6)
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(1a)
To guide your rocket until the rocket has reached a sufficient velocity where the fins take.

(1b)
The objective in both are convex lens

(1c)
m=v/u = 5/1*v/20
v=100cm
1/u+1/v=1/f
1/20+1/100=1/f
5+1/100=1/f
6/100 =1/f
F=(100/6)cm.

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(2a)
simple harmonic motion is a special type of periodic motion where the restoring force on the moving object is directly proportional to the object’s displacement magnitude and acts towards the object’s equilibrium position. It results in an oscillation which, if uninhibited by friction or any other dissipation of energy, continues indefinitely.

(2b)
Both of them acting a force i;e point
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(4a)
(i)water
(ii)Air

(4b)
X/100 =40-32/212-32
X/100 = 8/180
X=100*8/180= 800/180
=4.44°C
The temperature reading on B is 4.44°C
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(5a)
The principle of conservation of linear momentum states that the linear momentum of a system can be changed only if external forces acts on it.

(5b)
That is when momentum is considered but not in kinetic energy. That is kinetic energy usually decreases at it is converted.
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(7a)
2 represent amplitude

(7b)
Recall from y=A sin(2πft – 2π/x)
2πft = 400*0
F=400/2=200Hz
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(10)
15minute * 18*60=1080 second.
Then it reduced by 1/8 of 1080 = 135 second
T½= m²/λ where m² = 0.693
λ=0.693/T½ = 0.693/135 per second
λ=5.133*10^-³second

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(12ai)
Static friction is a force that keeps an object at rest.

(12aii)
(i)By polishing surface
(ii)By using lubricant

(12b)
Speed is the time rate at which an object is moving along a path while velocity is the rate and direction of an objects movement.

(12ci)
V=u+at (between A&B)
8=0+a*5
8/5=59/5
a=1.6m|s²

(12cii)
S = u + ½ at ²
S = 0*5+½*1.6*5²
S = 0+40/2
S = 0 + 20 = 20m
; Distance covered between A and B is 20m.

(12ciii)
S=(u+v/2) t
40⁴/2/5=(8+v)⁵/5

16=8+v
=16-8= 8m/s²

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(15a)
Coulomb’s law states that the electrical force between two charged objects is directly proportional to the product of the quantity of charge on.

(15bi)
Ratio of charge to potential different of the capacitor is I

(15bii)
Capacitance is directly proportional to the electrostatic force field between the plates

(15c)
Total resistance
R=R¹+ R²*R²/R²+R²
R=R¹+R²/2R
R=2R¹+R²/2
From ohm’s law
R=E/I
2R¹+R²/2=2E/I
4E/I=2R¹+R²
R²=4E/I-2R¹

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